Solution:
Let given matrix be A=[1011]
Now, A2=[1011]2=[1021]
Next, A3=A2.A=[1021].[1011]=[1031]
And so on.
Then, we observe that An=An−1.A=[10n−11].[1011]=[10n1]=[1001]
We see that for no value of n , we have An=I .
Thus, given matrix A is not cyclic.
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