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Answer to Question #14993 in Abstract Algebra for aunjelic
Question #14993
1. 4c-3=63 ?
2.3p+85=2p-10
3.6h+7=7h-5
4.14k-1=
5.7e-4=2e+13
2.3p+85=2p-10
3.6h+7=7h-5
4.14k-1=
5.7e-4=2e+13
Expert's answer
1. 4c-3=63
4с=63+3=66
с=66/4=33/2
2.3p+85=2p-10
3p-2p=-85-10
p=-95
3.6h+7=7h-5
7-5=7h-6h
h=2
4с=63+3=66
с=66/4=33/2
2.3p+85=2p-10
3p-2p=-85-10
p=-95
3.6h+7=7h-5
7-5=7h-6h
h=2
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