Let GGG be a group, HHH be a subgroup of GGG, ∣H∣=6,[G:H]>4|H|=6, [G:H]>4∣H∣=6,[G:H]>4 and ∣G∣<50|G|<50∣G∣<50. According to Lagrange's theorem, ∣G∣=∣H∣⋅[G:H]=6⋅[G:H]>6⋅4=24|G|=|H|\cdot[G:H]=6\cdot [G:H]>6\cdot 4=24∣G∣=∣H∣⋅[G:H]=6⋅[G:H]>6⋅4=24. Therefore, we conclude that
24<∣G∣<50.24<|G|<50.24<∣G∣<50.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments