Let "(G,*)" be a group containing at least 2 elements, and "e" be the identity of "(G,*)". Let "H=\\{e\\}". Recall that "e^{-1}=e" and "e*e=e." Then "(H,*)" is a subgroup of "(G,*)". If "a\\in G" and "a\\ne e", then "a^{-1}\\ne e" as well. Put "b=a^{-1}". Then "a*b=a*a^{-1}=e\\in H", but "a\\notin H" and "b\\notin H".
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