Let (G,∗)(G,*)(G,∗) be a group containing at least 2 elements, and eee be the identity of (G,∗)(G,*)(G,∗). Let H={e}H=\{e\}H={e}. Recall that e−1=ee^{-1}=ee−1=e and e∗e=e.e*e=e.e∗e=e. Then (H,∗)(H,*)(H,∗) is a subgroup of (G,∗)(G,*)(G,∗). If a∈Ga\in Ga∈G and a≠ea\ne ea=e, then a−1≠ea^{-1}\ne ea−1=e as well. Put b=a−1b=a^{-1}b=a−1. Then a∗b=a∗a−1=e∈Ha*b=a*a^{-1}=e\in Ha∗b=a∗a−1=e∈H, but a∉Ha\notin Ha∈/H and b∉Hb\notin Hb∈/H.
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