Question #138071
Find the quotient field of integral domain {a+ib such that a,b belongs to Z}
1
Expert's answer
2020-10-14T18:16:44-0400

Let KK be the quotient field of integral domain Z[i]={a+bi  a,bZ}\mathbb Z[i]=\{a+bi\ |\ a,b\in\mathbb Z\} and let Q(i)\mathbb Q(i) the field of complex numbers of the form r+sir+si with both rr and ss in Q\mathbb Q . Let us prove that K=Q(i)K=\mathbb Q(i).


First thing we need to convince yourseld that KQ(i)K\subset\mathbb Q(i). If we take a fraction a+bic+di\frac{a+bi}{c+di} with a,b,c,dZa,b,c,d\in\mathbb Z we can rewrite it as a+bic+di=ac+bdc2+d2+bcadc2+d2i\frac{a+bi}{c+di}=\frac{ac+bd}{c^2+d^2}+\frac{bc-ad}{c^2+d^2}i, and we're done.


On the other hand, if mn+pqiQ(i)\frac{m}{n}+\frac{p}{q}i\in\mathbb Q(i), we can rewrite this as nq+npinq\frac{nq+npi}{nq} where both numerator and denominator are Gaussian integers. Thus we also have Q(i)K\mathbb Q(i)\subset K and we're finished.



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS