Let K be the quotient field of integral domain Z[i]={a+bi ∣ a,b∈Z} and let Q(i) the field of complex numbers of the form r+si with both r and s in Q . Let us prove that K=Q(i).
First thing we need to convince yourseld that K⊂Q(i). If we take a fraction c+dia+bi with a,b,c,d∈Z we can rewrite it as c+dia+bi=c2+d2ac+bd+c2+d2bc−adi, and we're done.
On the other hand, if nm+qpi∈Q(i), we can rewrite this as nqnq+npi where both numerator and denominator are Gaussian integers. Thus we also have Q(i)⊂K and we're finished.
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