Question #138071

Find the quotient field of integral domain {a+ib such that a,b belongs to Z}

Expert's answer

Let KK be the quotient field of integral domain Z[i]={a+bi ∣ a,b∈Z}\mathbb Z[i]=\{a+bi\ |\ a,b\in\mathbb Z\} and let Q(i)\mathbb Q(i) the field of complex numbers of the form r+sir+si with both rr and ss in Q\mathbb Q . Let us prove that K=Q(i)K=\mathbb Q(i).


First thing we need to convince yourseld that K⊂Q(i)K\subset\mathbb Q(i). If we take a fraction a+bic+di\frac{a+bi}{c+di} with a,b,c,d∈Za,b,c,d\in\mathbb Z we can rewrite it as a+bic+di=ac+bdc2+d2+bc−adc2+d2i\frac{a+bi}{c+di}=\frac{ac+bd}{c^2+d^2}+\frac{bc-ad}{c^2+d^2}i, and we're done.


On the other hand, if mn+pqi∈Q(i)\frac{m}{n}+\frac{p}{q}i\in\mathbb Q(i), we can rewrite this as nq+npinq\frac{nq+npi}{nq} where both numerator and denominator are Gaussian integers. Thus we also have Q(i)⊂K\mathbb Q(i)\subset K and we're finished.



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