Obviously
"^{\\mathbb{Z}_{18}}\\!\/\\!_{<6>}= \\mathbb{Z}_6=\\{0,1,2,3,4,5\\}"
There are no elements of order 5 here because "ord(\\mathbb{Z}_6)=6" and order of any element must be a divisor of the group order, but "5\\nmid6"
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