Recall : A subspace W of a vector space V is called invariant under T iff T(W)"\\subset" W
Since U is given to be subspace of V so, 0 belongs to U
Now again U is subset of null space of V
Therefore , T(0)=0
For all u"\\in" U
We have T(u)=0 (because U is subset of null(T)
"\\forall" u"\\in" U , T(u)=0"\\in" U
So, T(U)"\\subset" U
Hence , U is invariant under T
Comments
Leave a comment