Answer to Question #250327 in Thermal Power Engineering for Bebe

Question

What is the KE of a body with a mass of 60 kg if it reaches the ground at 30 m

elevation at a velocity of 3.2 m/s? Express your answer in KJ.

Answer 1

$KE= \frac{1}{2}m × v^2$

m is mass =60kg

v is velocity = 3.2m/s

$KE = \frac{1}{2}×60 ×3.2^2$

$=307.2J =0.3072KJ$