Question

100 kg/min of steam at 34 bars, 340°C (h=3082.0kJ/kg) expands through a turbine isentropically until the pressure becomes 0.25 bars (h= 2540.37kJ/kg). Find the work in hp.

Answer 1

Work done in isentropically process is given by, $W = m(h_1 - h_2)$

So, Putting values,

$W = 100\times (3082.0 - 2540.37) = 54163 KJ$