Question #48240

Is the laplace transform of a double integral is [F(s)]/[s^2]
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Expert's answer

Answer on Question #48240, Engineering, Other

Question:

Is the laplace transform of a double integral is [F(s)]/[s2][F(s)]/[s^2]

Answer:

If G(s)=L{g(t)}G(s) = \mathcal{L}\{g(t)\}, then


L{0tg(t)dt}=G(s)s\mathcal{L} \left\{ \int_{0}^{t} g(t) \, dt \right\} = \frac{G(s)}{s}


Now if we have G(s)=L{g(t)}G'(s) = \mathcal{L}\{g'(t)\} and:


L{0tg(t)dt}=G(s)s\mathcal{L} \left\{ \int_{0}^{t} g'(t) \, dt \right\} = \frac{G'(s)}{s}g(t)=0tg(t)dtandG(s)=G(s)sg(t) = \int_{0}^{t} g'(t) \, dt \quad \text{and} \quad G(s) = \frac{G'(s)}{s}L{0tg(t)dt}=L{0t0tg(t)dtdt}=G(s)s=G(s)s2\mathcal{L} \left\{ \int_{0}^{t} g(t) \, dt \right\} = \mathcal{L} \left\{ \int_{0}^{t} \int_{0}^{t} g'(t) \, dt \, dt \right\} = \frac{G(s)}{s} = \frac{G'(s)}{s^2}


Answer: yes, it is.

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