Question

A refrigerator has to transfer an average of 263J of heat per second from -10'C to 25'C.Calculate the average power consumed .assume that the refrigerator is ideal.?

Answer 1

Answer on Question #47768, Engineering, Other

A refrigerator has to transfer an average of 263J of heat per second from -10°C to 25°C. Calculate the average power consumed. Assume that the refrigerator is ideal?

Solution:

Given:

$$\begin{array}{l} Q_{1} = 263 \mathrm{~J/s}, \\ T_{1} = 263 \mathrm{~K} \\ T_{2} = 298 \mathrm{~K}, \\ W = ? \end{array}$$

Get coefficient of performance for a Carnot Heat Pump Cooler :

Carnot Heat Pump Cooler

$$COP = \frac{T_{1}}{T_{2} - T_{1}} = \frac{263}{298 - 263} = 7.514$$

By definition :

$$COP = \frac{Q_{1}}{W}$$ $$W = \frac{Q_{1}}{COP} = \frac{263}{7.514} = 35 \mathrm{~W}$$

Answer: $W = 35 \mathrm{~W}$.

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