Question

A unit positive charged moves in an electric field E, along the path xyz, the voltage between point x and z ?

Answer 1

Answer on Question #47685-Engineering-Other

A unit positive charged moves in an electric field $E$, along the path $xyz$, the voltage between point $x$ and $z$?

Solution

The voltage difference between point $x$ and $z$ is

$$\Delta U = U_x - U_z = - \vec{E} \cdot (\vec{r}_x - \vec{r}_z) = E a.$$

Note that a positive charge can move only from $x$ to $z$, but not from $z$ to $x$. It is because of direction of an electric field $\vec{E}$.

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