Question #43499

Expand the following Boolean functions into their canonical form:
i. f(X,Y,Z)=XY+YZ+ X Z+ X Y
ii. f(X,Y,Z)=XY+ X Y + X YZ

Expert's answer

Answer on Question #43499, Engineering, Other

Expand the following Boolean functions into their canonical form:

i. f(X,Y,Z)=XY+YZ+XZ+XYf(X,Y,Z) = XY + YZ + XZ + XY

ii. f(X,Y,Z)=XY+XY+XYZf(X,Y,Z) = XY + XY + XYZ

Solution.


XY+YZ+XZ+XY=XY(Z+Z)+(X+X)YZ+X(Y+Y)Z+XY(Z+Z)=XYZ+XYZ+XYZ+XYZ+XYZ+XYZ+XYZ+XYZ=XYZ+XYZ+XYZ+XYZ+XYZ=m1+m2+m3+m6+m7\begin{array}{l} XY + YZ + X'Z + X'Y \\ = XY(Z + Z') + (X + X')YZ + X'(Y + Y')Z + X'Y(Z + Z') \\ = XYZ + XYZ' + XYZ + X'YZ + X'YZ + X'Y'Z + X'YZ \\ + X'YZ' = XYZ + XYZ' + X'YZ + X'Y'Z + X'YZ' \\ = m_1 + m_2 + m_3 + m_6 + m_7 \\ \end{array}


Answer: XY+YZ+XZ+XY=m1+m2+m3+m6+m7XY + YZ + X'Z + X'Y = m_1 + m_2 + m_3 + m_6 + m_7

XY+XY+XYZ=XY(Z+Z)+XY(Z+Z)+XYZ=XYZ+XYZ+XYZ+XYZ+XYZ=XYZ+XYZ+XYZ+XYZ=m2+m3+m6+m7\begin{array}{l} XY + X'Y + X'YZ = XY(Z + Z') + X'Y(Z + Z') + X'YZ \\ = XYZ + XYZ' + X'YZ + X'YZ' + X'YZ \\ = XYZ + XYZ' + X'YZ + X'YZ' = m_2 + m_3 + m_6 + m_7 \\ \end{array}


Answer: XY+XY+XYZ=m2+m3+m6+m7XY + X'Y + X'YZ = m_2 + m_3 + m_6 + m_7

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