Answer on Question #43499, Engineering, Other
Expand the following Boolean functions into their canonical form:
i. f(X,Y,Z)=XY+YZ+XZ+XY
ii. f(X,Y,Z)=XY+XY+XYZ
Solution.
XY+YZ+X′Z+X′Y=XY(Z+Z′)+(X+X′)YZ+X′(Y+Y′)Z+X′Y(Z+Z′)=XYZ+XYZ′+XYZ+X′YZ+X′YZ+X′Y′Z+X′YZ+X′YZ′=XYZ+XYZ′+X′YZ+X′Y′Z+X′YZ′=m1+m2+m3+m6+m7
Answer: XY+YZ+X′Z+X′Y=m1+m2+m3+m6+m7
XY+X′Y+X′YZ=XY(Z+Z′)+X′Y(Z+Z′)+X′YZ=XYZ+XYZ′+X′YZ+X′YZ′+X′YZ=XYZ+XYZ′+X′YZ+X′YZ′=m2+m3+m6+m7
Answer: XY+X′Y+X′YZ=m2+m3+m6+m7