Determine the force, F in lbf, required to lift a five gallon bucket full of water from rest with an acceleration of 3 m/s. Ignore the mass of the bucket.
Solution:
Let:
a=3m/c2V=5galonF=mg+mam=ρ∗V=1∗5∗4.546=22.73Kg;(1galon=4.546L)F=22.73∗9.8+22.73∗3=290.944N=65.41Lbf;(1Lbf=4.448N)
Answer: 65.41 lbf.
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