Question #74533

A lift cage of mass 826 kg accelerates uniformly upwards from rest to a velocity of 7 ms−1
whilst travelling a distance of 36 m. The frictional resistance to motion is 244 N. Making
use of the principle of conservation of energy, determine:

i) The work done
ii) The tension in the lifting cable
Iii) The average power developed

Expert's answer

Answer on Question #74533-Engineering-Mechanical Engineering

A lift cage of mass 826 kg accelerates uniformly upwards from rest to a velocity of 7 ms⁻¹ whilst travelling a distance of 36 m. The frictional resistance to motion is 244 N. Making use of the principle of conservation of energy, determine:

i) The work done

ii) The tension in the lifting cable

iii) The average power developed

Solution

i)


W=(mg+Ffr)h+m2v2=(826(9.8)+244)36+826272=320000JW = (mg + F_{fr})h + \frac{m}{2}v^2 = (826(9.8) + 244)36 + \frac{826}{2}7^2 = 320000\,J


ii)


T=(mg+Ffr)+maT = (mg + F_{fr}) + maa=v22ha = \frac{v^2}{2h}T=(mg+Ffr)+mv22h=(826(9.8)+244)+8262(36)72=8900NT = (mg + F_{fr}) + m\frac{v^2}{2h} = (826(9.8) + 244) + \frac{826}{2(36)}7^2 = 8900\,N


iii)


P=Tv2=((826(9.8)+244)+8262(36)72)72=31000W.P = T\frac{v}{2} = \left((826(9.8) + 244) + \frac{826}{2(36)}7^2\right)\frac{7}{2} = 31000\,W.


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