Determine the angle which the string would make with the horizontal,whan weights of the blocks A and B are such that
(a)WA=WB=W and
(b)WA=W,WB=2W.
1. Analyzing vertical forces where string 1 and string 2 meet, we find
T1=WAcosϕT_1 =\frac{W_A}{cos\phi}T1=cosϕWA N
2. Looking at the horizontal forces at that point leads to
T2=T1SinθT_2 =T_1Sin \thetaT2=T1Sinθ N
3.The angle of the string
θ=tan−1T2T1\theta =tan^{-1}\frac{T_2}{T_1}θ=tan−1T1T2
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