Question

Unpolarized light falls on two polarizing sheets placed one on top of the other. What must be the angle

between their transmission axis, if intensity of transmitted light by the analyzer is one third of that of

incident light?

Answer 1

$I_2=I_1cos^2\theta$

$\frac{1}{3}I_1=I_1cos^2\theta\implies \theta=cos^{-1}\frac{1}{√{3}}$

$\therefore \theta=55°$