Answer to Question #99296 in Electrical Engineering for Hardi Amiru Sulemana

Question #99296
An engine operating on the outo cycle has a compression ratio of 7.5:1. At the beginning of the compression stroke,the air is at 1.035bar and 27°C. If the heat energy supplied is 930Kj/kg of air, calculate; the maximum temperature and pressure in the cycle and the cycle efficiency
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Expert's answer
2019-11-25T07:26:55-0500

The Otto cycle consists of four stages:

1-2: adiabatic compression;

2-3: isochoric compression;

3-4: adiabatic expansion;

4-1: isochoric cooling.



Calculate the cycle thermal efficiency (for the air at the temperature of 27°C k=1.4):


ηth=11rk1=117.51.41=0.553.\eta_{th}=1-\frac{1}{r^{k-1}}=1-\frac{1}{7.5^{1.4-1}}=0.553.

At the end of the adiabatic compression:


T2=T1rk1=(273+27)71.41=671 K.T_2=T_1r^{k-1}=(273+27)7^{1.4-1}=671\text{ K}.


The pressure at 2 is


p2=rT2T1p1=7.5671300101325=1736213 Pa.p_2=r\frac{T_2}{T_1}p_1=7.5\cdot\frac{671}{300}\cdot101325=1736213\text{ Pa}.

The isochoric heat capacity:


cV=2.50.2871=0.71775 kJ/(kg-K).c_V=2.5\cdot0.2871=0.71775\text{ kJ/(kg-K)}.

The heat energy supplied:


930=q=cV(T3T2),930=q=c_V(T_3-T_2),

here T3T_3 is the maximum temp:


T3=qCV+T2=9300.71775+653=1949 K.T_3=\frac{q}{C_V}+T_2=\frac{930}{0.71775}+653=1949\text{ K}.

During the isochoric stage 2-3 the pressure reaches its maximum as well:


p2T2=p3T3, p3=p2T3T2=17362131949653=5043038 Pa,\frac{p_2}{T_2}=\frac{p_3}{T_3},\\ \space\\ p_3=p_2\frac{T_3}{T_2}=1736213\frac{1949}{653}=5043038\text{ Pa},

or 50.4 bar.


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