Usually a common sine wave is written as
where ω=2πf\omega=2\pi fω=2πf - angular frequency,
VRMS2=VampV_{RMS}\sqrt{2}=V_{amp}VRMS2=Vamp - amplitude (pike or maximum) value of the voltage,
ϕ\phiϕ - phase angle.
So in our problem the maximum amplitude voltage value is 10002=1414.2 V1000\sqrt{2}=1414.2\text{ V}10002=1414.2 V.
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