Question #79514

Suppose that Vmax value read from the graticule on an oscilloscope screen is 4.6 divisions and Vmin is 0.7 divisions. Calculate the modulation index and percentage of modulation.

Expert's answer

Answer on Question #79514 - Engineering - Electrical Engineering

Suppose that Vmax value read from the graticule on an oscilloscope screen is 4.6 divisions and Vmin is 0.7 divisions. Calculate the modulation index and percentage of modulation.

Solution

The modulation index is defined as


M=VmaxVmaxVmax+Vmax=4.60.74.6+0.7=0.736M = \frac {V _ {\mathrm {max}} - V _ {\mathrm {max}}}{V _ {\mathrm {max}} + V _ {\mathrm {max}}} = \frac {4.6 - 0.7}{4.6 + 0.7} = 0.736


The percentage of modulation is defined as


M%=M100%=0.736100%=73.6%M _ {\%} = M \cdot 100 \% = 0.736 \cdot 100 \% = 73.6 \%


Answer


M=0.736,M%=73.6%M = 0.736, M _ {\%} = 73.6 \%

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