Question

help me solve this mesh analyisis https://farm9.staticflickr.com/8666/28700367962_11bcbf275c_m.jpg

Answer 1

Answer on Question #61199-Engineering-Electrical Engineering

Help me solve this mesh analysis

3.36 Use mesh analysis to obtain i1,i2 and i3 in the circuit.

Solution

$$\left\{ \begin{array}{c} 12 + i_14 + (i_1 - i_2)6 = 0 \\ 10 + i_32 + (i_3 - i_2)6 = 0 \\ i_1 = i_2 + i_3 \end{array} \right. \to \left\{ \begin{array}{c} 2 + i_14 - i_32 + (i_1 - i_3)6 = 0 \\ 12 + i_14 + i_36 = 0 \end{array} \right. \to \left\{ \begin{array}{c} 2 + i_110 - i_38 = 0 \\ 12 + i_14 + i_36 = 0 \end{array} \right.$$ $$\rightarrow \left\{\begin{array}{c}i_1 = -\frac{27}{23}A \approx -1.174\,A\\i_3 = -\frac{28}{23}A \approx -1.217\,A\\i_2 = i_1 - i_3 = \frac{1}{23}A \approx 0.043\,A\end{array}\right.$$

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