Question #337519

if a force of 6900N is raised in a height of 15meters in 36 seconds what is the work done and the power developed?


1
Expert's answer
2022-05-06T01:48:03-0400

The work done

W=Fd=690015=103500JW=Fd=6900*15=103500\:\rm J

The power developed

P=Wt=10350036=2875WP=\frac{W}{t}=\frac{103500}{36}=2875\:\rm W


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