Question #337518

an energy source forces a constant current of 2.5amps for 20 seconds to flow through a light bulb. if 3kilojoules is given of in the form of light and heat energy calculate the charge of the current and the voltage drop across the bulb.


Expert's answer

The amount of charge

q=It=2.520=50Cq=It=2.5*20=50\:\rm C

The voltage drop

V=Wq=300050=60VV=\frac{W}{q}=\frac{3000}{50}=60\:\rm V


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