5. An 18mm diameter rivet is used to fasten two 22mm thick plate. If the
shearing stress is 60 MPA. What tensile force applied each plate to shear the
bolt?
( Ans F=15.27KN )
P=τArivetτ=60MPAArivet=π1824=81πmm2P=4860πN=15.27kNTensile force applied to shear the bolt is 15.27kNP=\tau{A_{rivet}}\\ \tau=60MPA\\ A_{rivet}=\frac{\pi18^2}{4}=81\pi{mm^2}\\ P=4860\pi{N}=15.27kN\\ \text{Tensile force applied to shear the bolt is 15.27kN}P=τArivetτ=60MPAArivet=4π182=81πmm2P=4860πN=15.27kNTensile force applied to shear the bolt is 15.27kN
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