Question

2. If the ultimate shear strength of a steel plate is 35000psi, what force is

necessary to punch a 0.35 in. diameter hole in a 0.255 in. thick plate?

( Ans F=9813.55 lb )

Answer 1

$$\sigma=\frac{F}{A}$$

$$F=\sigma A=\sigma\pi d t$$

$$F={\rm 35000\: psi\times3.14159\times 0.35\: in\times 0.255\: in}\\ =9813.55\:\rm lb$$