Question #278708

Derive and explain gauss’ law


Expert's answer

In electrostatics, the Gauss' theorem is


EdA=q/(ϵ0ϵ)\oint \vec Ed\vec A=\sum q/(\epsilon_0\epsilon)


The flux of the electrostatic field strength vector through an arbitrary closed surface is equal to the algebraic sum of the charges covered by this surface.


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