Answer to Question #278708 in Electrical Engineering for Victor

Question #278708

Derive and explain gauss’ law


1
Expert's answer
2021-12-15T07:24:02-0500

In electrostatics, the Gauss' theorem is


"\\oint \\vec Ed\\vec A=\\sum q\/(\\epsilon_0\\epsilon)"


The flux of the electrostatic field strength vector through an arbitrary closed surface is equal to the algebraic sum of the charges covered by this surface.


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