Derive and explain gauss’ law
In electrostatics, the Gauss' theorem is
∮E⃗dA⃗=∑q/(ϵ0ϵ)\oint \vec Ed\vec A=\sum q/(\epsilon_0\epsilon)∮EdA=∑q/(ϵ0ϵ)
The flux of the electrostatic field strength vector through an arbitrary closed surface is equal to the algebraic sum of the charges covered by this surface.
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