Question #275384

Two resistors when connected in series have a total resistance of 40 ohms and when connected in parallel

has a total resistance of 7.5 ohms. Find the value of each resistor in ohm 


1
Expert's answer
2021-12-07T05:07:04-0500

Write the formulas:


Rp=R1R2R1+R2=7.5. Rs=R1+R2=40. R1=40R2, 7.5=(40R2)R240, R2240R2+300=0, R2=10Ω,R1=30Ω;R1=10Ω,R2=30Ω.R_{p}=\frac{R_1R_2}{R_1+R_2}=7.5.\\\space\\ R_{s}=R_1+R_2=40.\\\space\\ R_1=40-R_2,\\\space\\ 7.5=\frac{(40-R_2)R_2}{40},\\\space\\ R_2^2-40R_2+300=0,\\\space\\ R_2=10\Omega, R_1=30\Omega;\\ R_1=10\Omega, R_2=30\Omega.


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