Question

A 12V battery has an internal resistance of 0.05Ω. Two loads are connected in parallel across its terminal, the first drawing a current of 12A and the other taking a power of 200 watts. Determine the load terminals voltage?

Answer 1

$I=E/(R+r)\to IR+0.05I=12\to$

$U+0.05I=12$

$I=I_1+I_2=12+200/U$ .So, we have

$U+(12+200/U)\cdot0.05=12$

$U^2-11.4U+10=0\to U=10.4\ (V)$ . Answer