1) Calculate the work that is done on the fluid of vertical layer thickness x1 and x2 in a pipe:
dW=F1dx1−F2dx2=p1A1dx1−p2A2dx2==p1dV−p2dV=(p1−p2)dV. 2) This work was done to change the kinetic and potential energy of the fluid:
dK=21m2v22−21m1v12=21ρ(v22−v12)dV, dU=mgh2−mgh1=ρg(h2−h1)dV, dW=dK+dU, (p1−p2)dV=21ρ(v22−v12)dV+ρg(h2−h1)dV.3) Rearrange the equation so all members with index 1 are on the left and all members with index 2 are on the right:
p1+21ρv12+ρgh1=p2+21ρv22+ρgh2.
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