Consider a message signal π(π‘) with bandwidth π = 2 ππ»π§ , applied to a DSB-SC modulator, s.t., π (π‘) = π΄ππ(π‘) cos(2πππ π‘). Assuming perfect synchronism between the carrier waves in the modulator and detector. a. Determine (sketch) the spectrum of the detector output when ππ = 1 ππ»π§. (Note: π(π) is shown in the figure, and π(0) = 1.) b. Find the lowest ππ for which each component of the modulated wave π (π‘) is uniquely determined by π(π‘). Sketch the spectrum of the detector output with the lowest ππ that you have required.Β
Vc(t) = Ec sinΟct β Vm(t) = Em sinΟmt β VAM(t) = Ec sinΟct + Em sinΟmt . sinΟct
We can express this as:
Β VAM(t) = [Ec + Em sinΟmt ]. sinΟct = [1+ m.sinΟmt ]. Ec. sinΟct
Comments
Leave a comment