A parallel-plate capacitor, having plates of 100c㎡ and has three
dielectrics 1mm each and of permittivity’s 3, 4 and 6. If the peak
voltage 2000V is applied to the plates, calculate the energy stored
in each dielectric
"V=100\\cdot10^{-4}\\cdot1\\cdot10^{-3}=10^{-5}\\ (m^3)"
"E=2000\/0.003=666667\\ (V\/m)"
"E_1=\\epsilon_1\\epsilon_0E^2V\/2=3\\cdot8.85\\cdot10^{-12}\\cdot666667^2\\cdot 10^{-5}\/2="
"=5.9\\cdot10^{-5}\\ (J)"
"E_2=\\epsilon_2\\epsilon_0E^2V\/2=4\\cdot8.85\\cdot10^{-12}\\cdot666667^2\\cdot 10^{-5}\/2="
"=7.84\\cdot10^{-5}\\ (J)"
"E_3=\\epsilon_3\\epsilon_0E^2V\/2=6\\cdot8.85\\cdot10^{-12}\\cdot666667^2\\cdot 10^{-5}\/2="
"=11.8\\cdot10^{-5}\\ (J)"
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