Answer to Question #245828 in Electrical Engineering for jinbitchon

Question

Two capacitors C1 and C2 of 1μf and 3μf are connected in parallel

across a voltage supply. At a particular instant when the applied

voltage is increasing positively, the two capacitors together draw a

current of 4A. Find the instantaneous rate of increase of potential

across them. 

Answer 1

Given

C1= 1uF

C2= 3uF

are connected in parallel

Total capacitance C= C1+C2=(1+3)uF=4 uF

$dV/dt= I/C$

= 4* 10^-6/4=1*10^-6

$dV/dt=1$0^-6 volt/time