Three resistors A,B , and C are connected in series to a 117 volt source . If RA= 64 ohms , and EB = 40 volts when the current is 0.5 amp , calculate the resistors RB and RC
"-117 + 64(0.5) + 40 + R_c(0.5) = 0\\\\\nR_c = \\frac{45}{0.5} = 90ohms\\\\\nR_b = \\frac{40}{0.5} = 80 ohms\\\\"
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