Question #239573
Assume an isotropic antenna operating at 10 GHz, find the effective area and antenna gain.
1
Expert's answer
2021-09-21T02:06:09-0400

The effective area 

Ae=kπD2446=10log10k(πD2λ)2πD2λ=269.04D=269.04λπ=269.040.0253.14=2.14Ae=kπD24=0.553.142.1424=1.98m2A_e=k \frac{\pi D^2}{4}\\ 46=10 \log_{10} k(\frac{\pi D^2}{\lambda})^2\\ \frac{\pi D^2}{\lambda}=269.04\\ D=\frac{269.04* \lambda}{\pi}=\frac{269.04* 0.025}{3.14}=2.14\\ \therefore A_e=k \frac{\pi D^2}{4}= \frac{0.55*3.14*2.14^2}{4}=1.98 m^2\\


Antenna gain

G=10log10k(πD2λ)2G=10log100.55(3.14300.075)2G=59.38dBG=10 \log_{10} k(\frac{\pi D^2}{\lambda})^2\\ G=10 \log_{10} *0.55*(\frac{3.14* 30}{0.075})^2\\ G=59.38dB


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