The effective area
Ae=kπD2446=10log10k(πD2λ)2πD2λ=269.04D=269.04∗λπ=269.04∗0.0253.14=2.14∴Ae=kπD24=0.55∗3.14∗2.1424=1.98m2A_e=k \frac{\pi D^2}{4}\\ 46=10 \log_{10} k(\frac{\pi D^2}{\lambda})^2\\ \frac{\pi D^2}{\lambda}=269.04\\ D=\frac{269.04* \lambda}{\pi}=\frac{269.04* 0.025}{3.14}=2.14\\ \therefore A_e=k \frac{\pi D^2}{4}= \frac{0.55*3.14*2.14^2}{4}=1.98 m^2\\Ae=k4πD246=10log10k(λπD2)2λπD2=269.04D=π269.04∗λ=3.14269.04∗0.025=2.14∴Ae=k4πD2=40.55∗3.14∗2.142=1.98m2
Antenna gain
G=10log10k(πD2λ)2G=10log10∗0.55∗(3.14∗300.075)2G=59.38dBG=10 \log_{10} k(\frac{\pi D^2}{\lambda})^2\\ G=10 \log_{10} *0.55*(\frac{3.14* 30}{0.075})^2\\ G=59.38dBG=10log10k(λπD2)2G=10log10∗0.55∗(0.0753.14∗30)2G=59.38dB
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