A single layer of No. 24 WGA (dia=0.0201) commercial iron wire is wound over a ceramic tube whose diameter is 3.25 in if the total wire resistance is 41 ohms, determine the number of turns.
Solution
Given data
Diameter (d)=0.0201 in
Resistance (R)=41"\\Omega"
Circumference of ceramic tube(c)"=\\pi D"
="\\pi\\frac{3.25}{12}=0.85ft" =1turn
And CM="\\frac{0.021}{0.001}=404.01mil^2"
Resistance
"R=\\rho \\frac{L}{CM}"
"L=R\\frac{CM}{\\rho}=\\frac{41\\times404.01}{75}=221ft"
No. of turns
"N=\\frac{L}{C}=\\frac{221}{0.85}=259.83"
"N=260"
Therefore number of turns are 260.
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