Given:
d=2m
H=7.95A/m
F/l=2.4∗10−10N
The magnetic intensity at a point mid way between the wires
H=H1+H2=2πd/2I1+2πd/2I1
H=πdI1+I2The force on each wire per unit length
F/l=μ02πdI1I2Using these equations, we get
I1+I2=2π∗7.95I1∗I2=2∗2.4∗10−10/10−7
I1+I2=50I1∗I2=0.0048Roots:
I1=50A,I2=9.6∗10−5A
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