A three phase induction motor is wound for 4 poles and is supplied from 50 Hz system. Calculate the rotor frequency when the rotor runs at 600 r.p.m.
Ns=120fp=120×504=1500 rpmNr=Ns(1−s)600=1500(1−s)s=1−615=0.6Rotor frequency is =sf=0.6×50=30 HertzN_s=\dfrac{120f}{p}=\dfrac{120\times{50}}{4}=1500\ rpm\\ N_r=N_s(1-s)\\ 600=1500(1-s)\\ s=1-\dfrac{6}{15}=0.6\\ Rotor\ frequency\ is\ =sf=0.6\times{50}=30\ HertzNs=p120f=4120×50=1500 rpmNr=Ns(1−s)600=1500(1−s)s=1−156=0.6Rotor frequency is =sf=0.6×50=30 Hertz
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments