Answer to Question #229826 in Electrical Engineering for Apostle

Question

An air filled rectangular waveguide has TE10 mode cut off frequency of 8Ghz. The signal frequency is 15 GHz and the ratio a/b is 2. If the waveguide is now filled with perplexed of relative permittivity 2.5 , find the guide wavelength of the signal.

Answer 1

Given that,

v = 299702547 m/s (light in air)

f = 15 GHz

Cutoff frequency = 8Ghz

Signal Frequency: 15Ghz

Ratio: 2

Relative permittivity= 2.5

=> We, Convert the Wave frequency (f) 15 MHz to " (Hz)"

F = 15 x 1000000

F = 15000000 Hz

Substitute the value into the formula

λ = 

299702547/15000000

λ = 19.98017 m

∴ Wavelength (λ) = 19.98017 m