Question #229609
A combinational circuit has four inputs (A,B,C,D), which represent a binarycoded-decimal digit. The
circuit has two groups of four outputs - S,T,U,V(MSB digit) and W,X,Y,Z.(LSB digit)Each group
represents a BCD digit. The output digits represent a decimal number which is five times the input
number. Illustrate the minimum expression for all the outputs?
Expert's answer
A
B
C
D
Output (per 5 Inputs )
S
T
U
V
W
X
Y
Z
0
0
0
0
50=00
0
0
0
0
0
0
0
0
0
0
0
1
51=05
0
0
0
0
0
1
0
1
0
0
1
0
52=10
0
0
0
1
0
0
0
0
0
0
1
1
53=15
0
0
0
1
0
1
0
1
0
1
0
0
54=20
0
0
1
0
0
0
0
0
0
1
0
1
55=25
0
0
1
0
0
1
0
1
0
1
1
0
56=30
0
0
1
1
0
0
0
0
0
1
1
1
57=35
0
0
1
1
0
1
0
1
1
0
0
0
58=40
0
1
0
0
0
0
0
0
1
0
0
1
59=45
0
1
0
0
0
1
0
1
We first established that the connection between input and output is X5:
Therefore, the 4 outputs ABCD gives us the minimal expression of the provided inputs
However, codes such as 1010 and 1111 become null and do not come up as inputs as shown
above.
