Consider an unbalanced phasor has shown in (a). The positive, negative, and zero sequence are shown in (b), (c), and (d) respectively.
Let's define the a-operator
a=ej120°=−21+j23a2=ej240°=−21−j23
from (b)
Vb1=a2Va1Vc1=aVa1
from (c)
Vb2=aVa2Vc2=a2Va2
from (d)
Va0=Vb0=Vc0
Va=Va0+Va1+Va2Vb=Vb0+Vb1+Vb2Vb=Va0+a2Va1+aVa2Vc=Vc0+Vc1+Vc2Vc=Va0+aVa1+a2Va2
Comments
Leave a comment