Question #226503

Show that, "Three unbalanced phasors of a 3- system can be resolved into three balanced system of phasors."


Expert's answer


Consider an unbalanced phasor has shown in (a). The positive, negative, and zero sequence are shown in (b), (c), and (d) respectively.

Let's define the a-operator

a=ej120°=−12+j32a2=ej240°=−12−j32a=e^{j120\degree}=-\dfrac{1}{2}+j\dfrac{\sqrt{3}}{2}\\ a^2=e^{j240\degree}=-\dfrac{1}{2}-j\dfrac{\sqrt{3}}{2}\\

from (b)

Vb1=a2Va1Vc1=aVa1V_{b1}=a^2V_{a1}\\ V_{c1}=aV_{a1}\\

from (c)

Vb2=aVa2Vc2=a2Va2V_{b2}=aV_{a2}\\ V_{c2}=a^2V_{a2}

from (d)

Va0=Vb0=Vc0V_{a0}=V_{b0}=V_{c0}



Va=Va0+Va1+Va2Vb=Vb0+Vb1+Vb2Vb=Va0+a2Va1+aVa2Vc=Vc0+Vc1+Vc2Vc=Va0+aVa1+a2Va2V_{a}=V_{a0}+V_{a1}+V_{a2}\\ V_{b}=V_{b0}+V_{b1}+V_{b2}\\ V_{b}=V_{a0}+a^2V_{a1}+aV_{a2}\\ V_{c}=V_{c0}+V_{c1}+V_{c2}\\ V_{c}=V_{a0}+aV_{a1}+a^2V_{a2}\\



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