Answer to Question #225498 in Electrical Engineering for Zoe

Question #225498
Question 4
4.1 An interconnected 50 Hz power system consisting of one area has two
turbine-generator units, rated 600 and 800 MVA, with regulation constants
of 0.04 and 0.06 per unit, respectively, based on their respective ratings.
When each unit carries a 350 MVA steady-state load, let the area load
suddenly increase by 250 MVA. Determine:
4.1.1 The area frequency response characteristic on a 1000 MVA base. (5)
4.1.2 ∆
1
Expert's answer
2021-08-16T02:20:35-0400

The regulation constant

"R_{1}{new}= 0.04* \\frac{1000}{600}=0.0667p.u\\\\\nR_{2}{new}= 0.06* \\frac{1000}{800}=0.075"

The value of unit area frequency response characteristic

"\\beta= \\frac{1}{0.0667}+\\frac{1}{0.075}= 28.33p.u"

Per unit value

"\\Delta p_m = \\frac{250}{1000}= 2.5 p.u"

Consider the expression for the steady state frequency power relation.

"\\Delta p= \\Delta p_{ref}- \\beta\\Delta f"

For the steady state operation, the value of "\\Delta p_{ref}" is 0

"\\Delta p= - \\beta\\Delta f\\\\\n\\Delta f = -\\frac{2.5}{28.33}=-0.0882"

The negative sign represents a decrease in the value of frequency. Therefore, the steady-state value of the area frequency is 0.0882

The steady-state area value of the area frequency in hertz

"\\Delta f _{hertz} =-0.0882*50=-4.4123Hz"


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