I=PVRcos(ϕR)=5000×10011000×0.8=568.18AI = \frac{P}{V_R cos(\phi_R)} = \frac{5000\times 100}{11000\times 0.8}=568.18AI=VRcos(ϕR)P=11000×0.85000×100=568.18A
Line loss, I2R=(568.182×0.45)=145.27KWI^2R = (568.18^2 \times 0.45) = 145.27 KWI2R=(568.182×0.45)=145.27KW
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