4^(×)+4^(×+1)+3=0
Simplify
4(x)+4(x+1)+3=04(x+1)+x+3=042x+1=−342x=−34af(x) cannot be zero or negative for x∈RNo Solution for x∈R4^{\left(x\right)}+4^{\left(x+1\right)}+3=0\\ 4^{\left(x+1\right)+x}+3=0\\ 4^{2x+1}=-3\\ 4^{2x}=-\frac{3}{4}\\ a^{f\left(x\right)}\mathrm{\:cannot\:be\:zero\:or\:negative\:for\:}x\in \mathbb{R}\\ \mathrm{No\:Solution\:for}\:x\in \mathbb{R}4(x)+4(x+1)+3=04(x+1)+x+3=042x+1=−342x=−43af(x)cannotbezeroornegativeforx∈RNoSolutionforx∈R
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