Answer to Question #213783 in Electrical Engineering for Ieje

Question

 A 220V, 50 Hz, 6 pole, Y connected alternator with resistance 0.06 Ω per phase gave

the following data for open circuit and Short circuit characteristics.

Answer 1

The induced e.m.f per phase can be calculated as follows

Armature current

$I_a= \frac{S}{\sqrt{3}*V_L}= \frac{10*10^6}{\sqrt{3}*220} = 26243.19 A\\$

Synchronous impedance,

$Z_s=R_a+jX_s = 0.07+j0.06 \Omega = 1.901\angle 87.89^0 \Omega$