Answer to Question #206770 in Electrical Engineering for Mostafiz

Question

Insulator capacitance of MOSFET 10 micro F . width of depletion layer 0.2 cm and permitivity is 33 . calculate total capacitance

Answer 1

$C_{dep}=\frac{\epsilon}{w_{dep}}\newline \epsilon=33 \newline w_{dep}=0.2cm=0.002m \newline C_{in}=10\mu F \newline C_{dep}=\frac{33} {0.002}=16500F=0.0165\mu F \newline$

Total capacitance is

$(C)=\frac{C_{dep} \times C_{in}}{C_{dep} + C_{in}} \newline C=\frac {0.0165 \times 10}{0.0165+10} \newline C=\frac {0.165}{10.0165} \newline C= 0.0165\mu F=16.5nF$