The saturation current will be the twice of the diode current. and contact potential of the diode is 33 Volt. calculate the temperature.
Ideal diode equation is given by
I=I_o(e^{\frac {qV}{kT}}-1)
Diode current=I
Saturation current= I_o
Electron charge=q
Contact voltage=V
Boltzmann's constant=k
Temperature= T
Making T the subject of the formula
T= \frac {\frac {qV}{k}}{\ln(\frac{I}{I_o}+1)}
q=1.6 \times 10^{-19}C
V=33v
k= 1.38 \times 10^{-23}m^2kgs^{-2}K^{-1}
I_o=2\times I
T= \frac {\frac {1.6 \times 10^{-19} \times 33}{1.38 \times 10^{-23}}}{\ln(\frac{I}{2 \times I}+1)}
T= \frac{382608.69}{\ln1.5}
T=943629K
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