For high -pass active filter with corner frequency 8 kHz, then R and C are:
Select one :
a. 2.5kΩ ,7.9557nF
b. 2 kΩ ,7.9557nF
c. 5kΩ ,7.9557nF
d. 10kΩ ,7.9557nF
e. 1kΩ ,7.9557nF
ν=12πRC→12⋅3.14⋅2500⋅7.9557⋅10−9≈8000 (Hz)\\\nu=\frac{1}{2\pi RC}\to\frac{1}{2\cdot3.14\cdot2500\cdot7.9557\cdot10^{-9}}\approx8000\ (Hz)ν=2πRC1→2⋅3.14⋅2500⋅7.9557⋅10−91≈8000 (Hz) . So,
a. 2.5kΩ ,7.9557nF. Answer
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