Answer to Question #205646 in Electrical Engineering for wea

Question

In 3 phase system, the power was measured by using two wattmeter's method the first wattmeter's reading was 1600 Watt and the second wattmeter's reading was - 100 Watt the total power of the system is:

Select one:

A. 1600 Watt

B. 1500 Watt

C. 1700 Watt

Answer 1

Total power of the system is

P_T = P_1 + P_2

P_1 = 1600 Watts

P_2 = -100 Watts

P_T = 1600-100

P_T = 1500 Watts

Answer

(B)