Find the volume of the solid generated by revolving about the x-axis bounded by the curve, y2 = 9x and the line y = 3x
R.E.F image
y=3xy=3xy=3x
y2=ax2y^ 2 =ax ^ 2y2=ax2
ax=ax2ax=ax ^ 2ax=ax2
x=0,x=1x=0,x=1x=0,x=1
Area bounded =∫01(3x−3x)dx=∫ _ 0^ 1 (3\sqrt{ x} −3x)dx=∫01(3x−3x)dx
=[32x3/23−3x22]01=[ \frac{32x ^{3/2}}{3} − \frac{3x^2}{2}] _0^ 1 =[332x3/2−23x2]01
=2−32=1/2sq.units=2− \frac{3}{2} =1/2 sq.units=2−23=1/2sq.units
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