Question #202745

The metal bar is AB =10mm, DA=18mm, BC =220cm and the resistivity of the metal is 0,012 micro ohms. what is its tip to tip resistance


1
Expert's answer
2021-06-08T06:53:02-0400

Resistance of a conductor of uniform section SS is R=ρlSR =\frac{\rho l}{S}, where ρ\rho is electrical resistivity, ll is length.

The area of the cross section of the bar is S=10103m18103m=1.8104m2S = 10 \cdot 10^{-3} m \cdot 18 \cdot 10^{-3} m = 1.8 \cdot 10^{-4} m^2, and the length is l=2.2ml = 2.2 m. Hence, the resistance is:

R=0.012106Ωm 2.2m1.8104m21.5104ΩR = \frac{0.012 \cdot 10^{-6} \Omega \cdot m \ 2.2 m\cdot }{1.8 \cdot 10^{-4} m^2} \approx 1.5 \cdot 10^{-4} \Omega.


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